3(2x-8)+20=-40

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Solution for 3(2x-8)+20=-40 equation: 



3(2x-8)+20=-40

We move all terms to the left:

3(2x-8)+20-(-40)=0

We add all the numbers together, and all the variables

3(2x-8)+60=0

We multiply parentheses

6x-24+60=0

We add all the numbers together, and all the variables

6x+36=0

We move all terms containing x to the left, all other terms to the right

6x=-36

x=-36/6

x=-6

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