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3(2x-8)-2=3(x-4)+10
We move all terms to the left:
3(2x-8)-2-(3(x-4)+10)=0
We multiply parentheses
6x-(3(x-4)+10)-24-2=0
We calculate terms in parentheses: -(3(x-4)+10), so:We add all the numbers together, and all the variables
3(x-4)+10
We multiply parentheses
3x-12+10
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
6x-(3x-2)-26=0
We get rid of parentheses
6x-3x+2-26=0
We add all the numbers together, and all the variables
3x-24=0
We move all terms containing x to the left, all other terms to the right
3x=24
x=24/3
x=8
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