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3(2x-9)-2=3(x-3)+7
We move all terms to the left:
3(2x-9)-2-(3(x-3)+7)=0
We multiply parentheses
6x-(3(x-3)+7)-27-2=0
We calculate terms in parentheses: -(3(x-3)+7), so:We add all the numbers together, and all the variables
3(x-3)+7
We multiply parentheses
3x-9+7
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
6x-(3x-2)-29=0
We get rid of parentheses
6x-3x+2-29=0
We add all the numbers together, and all the variables
3x-27=0
We move all terms containing x to the left, all other terms to the right
3x=27
x=27/3
x=9
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