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3(2x-9)=3(16-x)
We move all terms to the left:
3(2x-9)-(3(16-x))=0
We add all the numbers together, and all the variables
3(2x-9)-(3(-1x+16))=0
We multiply parentheses
6x-(3(-1x+16))-27=0
We calculate terms in parentheses: -(3(-1x+16)), so:We get rid of parentheses
3(-1x+16)
We multiply parentheses
-3x+48
Back to the equation:
-(-3x+48)
6x+3x-48-27=0
We add all the numbers together, and all the variables
9x-75=0
We move all terms containing x to the left, all other terms to the right
9x=75
x=75/9
x=8+1/3
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