3(2y+)=(y-2)(4)

Solution for 3(2y+)=(y-2)(4) equation:

3(2y+)=(y-2)(4)

We move all terms to the left:

3(2y+)-((y-2)(4))=0

We add all the numbers together, and all the variables

3(+2y)-((y-2)4)=0

We multiply parentheses

6y-((y-2)4)=0


We calculate terms in parentheses: -((y-2)4), so:

(y-2)4

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)


We get rid of parentheses

6y-4y+8=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4