3(2y+1)-(y-2)=-2(y+4)

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Solution for 3(2y+1)-(y-2)=-2(y+4) equation: 



3(2y+1)-(y-2)=-2(y+4)

We move all terms to the left:

3(2y+1)-(y-2)-(-2(y+4))=0

We multiply parentheses

6y-(y-2)-(-2(y+4))+3=0

We get rid of parentheses

6y-y-(-2(y+4))+2+3=0



We calculate terms in parentheses: -(-2(y+4)), so:

-2(y+4)

We multiply parentheses

-2y-8

Back to the equation:

-(-2y-8)



We add all the numbers together, and all the variables

5y-(-2y-8)+5=0

We get rid of parentheses

5y+2y+8+5=0

We add all the numbers together, and all the variables

7y+13=0

We move all terms containing y to the left, all other terms to the right

7y=-13

y=-13/7

y=-1+6/7

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