3(2y+1)-2=6(y-2)+14

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Solution for 3(2y+1)-2=6(y-2)+14 equation:


Simplifying
3(2y + 1) + -2 = 6(y + -2) + 14

Reorder the terms:
3(1 + 2y) + -2 = 6(y + -2) + 14
(1 * 3 + 2y * 3) + -2 = 6(y + -2) + 14
(3 + 6y) + -2 = 6(y + -2) + 14

Reorder the terms:
3 + -2 + 6y = 6(y + -2) + 14

Combine like terms: 3 + -2 = 1
1 + 6y = 6(y + -2) + 14

Reorder the terms:
1 + 6y = 6(-2 + y) + 14
1 + 6y = (-2 * 6 + y * 6) + 14
1 + 6y = (-12 + 6y) + 14

Reorder the terms:
1 + 6y = -12 + 14 + 6y

Combine like terms: -12 + 14 = 2
1 + 6y = 2 + 6y

Add '-6y' to each side of the equation.
1 + 6y + -6y = 2 + 6y + -6y

Combine like terms: 6y + -6y = 0
1 + 0 = 2 + 6y + -6y
1 = 2 + 6y + -6y

Combine like terms: 6y + -6y = 0
1 = 2 + 0
1 = 2

Solving
1 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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