3(2y+1)-4(y-3)=12

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Solution for 3(2y+1)-4(y-3)=12 equation: 


Simplifying
3(2y + 1) + -4(y + -3) = 12

Reorder the terms:
3(1 + 2y) + -4(y + -3) = 12
(1 * 3 + 2y * 3) + -4(y + -3) = 12
(3 + 6y) + -4(y + -3) = 12

Reorder the terms:
3 + 6y + -4(-3 + y) = 12
3 + 6y + (-3 * -4 + y * -4) = 12
3 + 6y + (12 + -4y) = 12

Reorder the terms:
3 + 12 + 6y + -4y = 12

Combine like terms: 3 + 12 = 15
15 + 6y + -4y = 12

Combine like terms: 6y + -4y = 2y
15 + 2y = 12

Solving
15 + 2y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + 2y = 12 + -15

Combine like terms: 15 + -15 = 0
0 + 2y = 12 + -15
2y = 12 + -15

Combine like terms: 12 + -15 = -3
2y = -3

Divide each side by '2'.
y = -1.5

Simplifying
y = -1.5

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