3(2y+1)-5=2(3y-4)

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Solution for 3(2y+1)-5=2(3y-4) equation: 



3(2y+1)-5=2(3y-4)

We move all terms to the left:

3(2y+1)-5-(2(3y-4))=0

We multiply parentheses

6y-(2(3y-4))+3-5=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We add all the numbers together, and all the variables

6y-(6y-8)-2=0

We get rid of parentheses

6y-6y+8-2=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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