3(2y+1)=17

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Solution for 3(2y+1)=17 equation: 



3(2y+1)=17

We move all terms to the left:

3(2y+1)-(17)=0

We multiply parentheses

6y+3-17=0

We add all the numbers together, and all the variables

6y-14=0

We move all terms containing y to the left, all other terms to the right

6y=14

y=14/6

y=2+1/3

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