3(2y+1)=5(y-2)+16

Solution for 3(2y+1)=5(y-2)+16 equation:

Simplifying
3(2y + 1) = 5(y + -2) + 16

Reorder the terms:
3(1 + 2y) = 5(y + -2) + 16
(1 * 3 + 2y * 3) = 5(y + -2) + 16
(3 + 6y) = 5(y + -2) + 16

Reorder the terms:
3 + 6y = 5(-2 + y) + 16
3 + 6y = (-2 * 5 + y * 5) + 16
3 + 6y = (-10 + 5y) + 16

Reorder the terms:
3 + 6y = -10 + 16 + 5y

Combine like terms: -10 + 16 = 6
3 + 6y = 6 + 5y

Solving
3 + 6y = 6 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
3 + 6y + -5y = 6 + 5y + -5y

Combine like terms: 6y + -5y = 1y
3 + 1y = 6 + 5y + -5y

Combine like terms: 5y + -5y = 0
3 + 1y = 6 + 0
3 + 1y = 6

Add '-3' to each side of the equation.
3 + -3 + 1y = 6 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = 6 + -3
1y = 6 + -3

Combine like terms: 6 + -3 = 3
1y = 3

Divide each side by '1'.
y = 3

Simplifying
y = 3