3(2y+1)=8(y-2)

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Solution for 3(2y+1)=8(y-2) equation:



3(2y+1)=8(y-2)
We move all terms to the left:
3(2y+1)-(8(y-2))=0
We multiply parentheses
6y-(8(y-2))+3=0
We calculate terms in parentheses: -(8(y-2)), so:
8(y-2)
We multiply parentheses
8y-16
Back to the equation:
-(8y-16)
We get rid of parentheses
6y-8y+16+3=0
We add all the numbers together, and all the variables
-2y+19=0
We move all terms containing y to the left, all other terms to the right
-2y=-19
y=-19/-2
y=9+1/2

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