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3(2y+10)=5(y+2)
We move all terms to the left:
3(2y+10)-(5(y+2))=0
We multiply parentheses
6y-(5(y+2))+30=0
We calculate terms in parentheses: -(5(y+2)), so:We get rid of parentheses
5(y+2)
We multiply parentheses
5y+10
Back to the equation:
-(5y+10)
6y-5y-10+30=0
We add all the numbers together, and all the variables
y+20=0
We move all terms containing y to the left, all other terms to the right
y=-20
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