3(2y+3)=-3(y-5)

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Solution for 3(2y+3)=-3(y-5) equation: 



3(2y+3)=-3(y-5)

We move all terms to the left:

3(2y+3)-(-3(y-5))=0

We multiply parentheses

6y-(-3(y-5))+9=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We get rid of parentheses

6y+3y-15+9=0

We add all the numbers together, and all the variables

9y-6=0

We move all terms containing y to the left, all other terms to the right

9y=6

y=6/9

y=2/3

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