3(2y+3)=33

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Solution for 3(2y+3)=33 equation: 



3(2y+3)=33

We move all terms to the left:

3(2y+3)-(33)=0

We multiply parentheses

6y+9-33=0

We add all the numbers together, and all the variables

6y-24=0

We move all terms containing y to the left, all other terms to the right

6y=24

y=24/6

y=4

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