3(2y+3)=67+9

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Solution for 3(2y+3)=67+9 equation: 



3(2y+3)=67+9

We move all terms to the left:

3(2y+3)-(67+9)=0

We add all the numbers together, and all the variables

3(2y+3)-76=0

We multiply parentheses

6y+9-76=0

We add all the numbers together, and all the variables

6y-67=0

We move all terms containing y to the left, all other terms to the right

6y=67

y=67/6

y=11+1/6

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