3(2y+4)=-2(y-5)

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Solution for 3(2y+4)=-2(y-5) equation: 



3(2y+4)=-2(y-5)

We move all terms to the left:

3(2y+4)-(-2(y-5))=0

We multiply parentheses

6y-(-2(y-5))+12=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

6y+2y-10+12=0

We add all the numbers together, and all the variables

8y+2=0

We move all terms containing y to the left, all other terms to the right

8y=-2

y=-2/8

y=-1/4

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