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3(2y+4)=5(y-23)
We move all terms to the left:
3(2y+4)-(5(y-23))=0
We multiply parentheses
6y-(5(y-23))+12=0
We calculate terms in parentheses: -(5(y-23)), so:We get rid of parentheses
5(y-23)
We multiply parentheses
5y-115
Back to the equation:
-(5y-115)
6y-5y+115+12=0
We add all the numbers together, and all the variables
y+127=0
We move all terms containing y to the left, all other terms to the right
y=-127
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