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3(2y+4)=6(5y+2)
We move all terms to the left:
3(2y+4)-(6(5y+2))=0
We multiply parentheses
6y-(6(5y+2))+12=0
We calculate terms in parentheses: -(6(5y+2)), so:We get rid of parentheses
6(5y+2)
We multiply parentheses
30y+12
Back to the equation:
-(30y+12)
6y-30y-12+12=0
We add all the numbers together, and all the variables
-24y=0
y=0/-24
y=0
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