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3(2y+5)=2(4y-3)
We move all terms to the left:
3(2y+5)-(2(4y-3))=0
We multiply parentheses
6y-(2(4y-3))+15=0
We calculate terms in parentheses: -(2(4y-3)), so:We get rid of parentheses
2(4y-3)
We multiply parentheses
8y-6
Back to the equation:
-(8y-6)
6y-8y+6+15=0
We add all the numbers together, and all the variables
-2y+21=0
We move all terms containing y to the left, all other terms to the right
-2y=-21
y=-21/-2
y=10+1/2
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