3(2y+5)=7(y-9)

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Solution for 3(2y+5)=7(y-9) equation: 



3(2y+5)=7(y-9)

We move all terms to the left:

3(2y+5)-(7(y-9))=0

We multiply parentheses

6y-(7(y-9))+15=0



We calculate terms in parentheses: -(7(y-9)), so:

7(y-9)

We multiply parentheses

7y-63

Back to the equation:

-(7y-63)



We get rid of parentheses

6y-7y+63+15=0

We add all the numbers together, and all the variables

-1y+78=0

We move all terms containing y to the left, all other terms to the right

-y=-78

y=-78/-1

y=+78

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