3(2y-1)+7=6y-3-2(2-4y)

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Solution for 3(2y-1)+7=6y-3-2(2-4y) equation:



3(2y-1)+7=6y-3-2(2-4y)
We move all terms to the left:
3(2y-1)+7-(6y-3-2(2-4y))=0
We add all the numbers together, and all the variables
3(2y-1)-(6y-3-2(-4y+2))+7=0
We multiply parentheses
6y-(6y-3-2(-4y+2))-3+7=0
We calculate terms in parentheses: -(6y-3-2(-4y+2)), so:
6y-3-2(-4y+2)
determiningTheFunctionDomain 6y-2(-4y+2)-3
We multiply parentheses
6y+8y-4-3
We add all the numbers together, and all the variables
14y-7
Back to the equation:
-(14y-7)
We add all the numbers together, and all the variables
6y-(14y-7)+4=0
We get rid of parentheses
6y-14y+7+4=0
We add all the numbers together, and all the variables
-8y+11=0
We move all terms containing y to the left, all other terms to the right
-8y=-11
y=-11/-8
y=1+3/8

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