3(2y-1)-1=4(y+1)+2

Solution for 3(2y-1)-1=4(y+1)+2 equation:

3(2y-1)-1=4(y+1)+2

We move all terms to the left:

3(2y-1)-1-(4(y+1)+2)=0

We multiply parentheses

6y-(4(y+1)+2)-3-1=0


We calculate terms in parentheses: -(4(y+1)+2), so:

4(y+1)+2

We multiply parentheses

4y+4+2

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)


We add all the numbers together, and all the variables

6y-(4y+6)-4=0

We get rid of parentheses

6y-4y-6-4=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5