3(2y-1)-2(y-2)=4(y+3)

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Solution for 3(2y-1)-2(y-2)=4(y+3) equation:


Simplifying
3(2y + -1) + -2(y + -2) = 4(y + 3)

Reorder the terms:
3(-1 + 2y) + -2(y + -2) = 4(y + 3)
(-1 * 3 + 2y * 3) + -2(y + -2) = 4(y + 3)
(-3 + 6y) + -2(y + -2) = 4(y + 3)

Reorder the terms:
-3 + 6y + -2(-2 + y) = 4(y + 3)
-3 + 6y + (-2 * -2 + y * -2) = 4(y + 3)
-3 + 6y + (4 + -2y) = 4(y + 3)

Reorder the terms:
-3 + 4 + 6y + -2y = 4(y + 3)

Combine like terms: -3 + 4 = 1
1 + 6y + -2y = 4(y + 3)

Combine like terms: 6y + -2y = 4y
1 + 4y = 4(y + 3)

Reorder the terms:
1 + 4y = 4(3 + y)
1 + 4y = (3 * 4 + y * 4)
1 + 4y = (12 + 4y)

Add '-4y' to each side of the equation.
1 + 4y + -4y = 12 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 + 0 = 12 + 4y + -4y
1 = 12 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 = 12 + 0
1 = 12

Solving
1 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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