3(2y-1)=2(4y-5)

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Solution for 3(2y-1)=2(4y-5) equation: 



3(2y-1)=2(4y-5)

We move all terms to the left:

3(2y-1)-(2(4y-5))=0

We multiply parentheses

6y-(2(4y-5))-3=0



We calculate terms in parentheses: -(2(4y-5)), so:

2(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)



We get rid of parentheses

6y-8y+10-3=0

We add all the numbers together, and all the variables

-2y+7=0

We move all terms containing y to the left, all other terms to the right

-2y=-7

y=-7/-2

y=3+1/2

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