3(2y-1)=4(3y-2)

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Solution for 3(2y-1)=4(3y-2) equation: 



3(2y-1)=4(3y-2)

We move all terms to the left:

3(2y-1)-(4(3y-2))=0

We multiply parentheses

6y-(4(3y-2))-3=0



We calculate terms in parentheses: -(4(3y-2)), so:

4(3y-2)

We multiply parentheses

12y-8

Back to the equation:

-(12y-8)



We get rid of parentheses

6y-12y+8-3=0

We add all the numbers together, and all the variables

-6y+5=0

We move all terms containing y to the left, all other terms to the right

-6y=-5

y=-5/-6

y=5/6

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