3(2y-2)+15=5(y-2)-(0y+4)

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Solution for 3(2y-2)+15=5(y-2)-(0y+4) equation: 



3(2y-2)+15=5(y-2)-(0y+4)

We move all terms to the left:

3(2y-2)+15-(5(y-2)-(0y+4))=0

We add all the numbers together, and all the variables

3(2y-2)-(5(y-2)-(y+4))+15=0

We multiply parentheses

6y-(5(y-2)-(y+4))-6+15=0



We calculate terms in parentheses: -(5(y-2)-(y+4)), so:

5(y-2)-(y+4)

We multiply parentheses

5y-(y+4)-10

We get rid of parentheses

5y-y-4-10

We add all the numbers together, and all the variables

4y-14

Back to the equation:

-(4y-14)



We add all the numbers together, and all the variables

6y-(4y-14)+9=0

We get rid of parentheses

6y-4y+14+9=0

We add all the numbers together, and all the variables

2y+23=0

We move all terms containing y to the left, all other terms to the right

2y=-23

y=-23/2

y=-11+1/2

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