3(2y-2)+6=6y

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Solution for 3(2y-2)+6=6y equation: 



3(2y-2)+6=6y

We move all terms to the left:

3(2y-2)+6-(6y)=0

We add all the numbers together, and all the variables

-6y+3(2y-2)+6=0

We multiply parentheses

-6y+6y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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