3(2y-2)/2=4y-5

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Solution for 3(2y-2)/2=4y-5 equation: 


y in (-oo:+oo)

(3*(2*y-2))/2 = 4*y-5 // - 4*y-5

(3*(2*y-2))/2-(4*y)+5 = 0

(3*(2*y-2))/2-4*y+5 = 0

(3*(2*y-2))/2+(-4*2*y)/2+(2*5)/2 = 0

3*(2*y-2)-4*2*y+2*5 = 0

10-2*y-6 = 0

4-2*y = 0

(4-2*y)/2 = 0

(4-2*y)/2 = 0 // * 2

4-2*y = 0

4-2*y = 0 // - 4

-2*y = -4 // : -2

y = -4/(-2)

y = 2

y = 2

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