3(2y-3)=4(4y+3)

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Solution for 3(2y-3)=4(4y+3) equation: 



3(2y-3)=4(4y+3)

We move all terms to the left:

3(2y-3)-(4(4y+3))=0

We multiply parentheses

6y-(4(4y+3))-9=0



We calculate terms in parentheses: -(4(4y+3)), so:

4(4y+3)

We multiply parentheses

16y+12

Back to the equation:

-(16y+12)



We get rid of parentheses

6y-16y-12-9=0

We add all the numbers together, and all the variables

-10y-21=0

We move all terms containing y to the left, all other terms to the right

-10y=21

y=21/-10

y=-2+1/10

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