3(2y-3)=5y+2(3-y)

Solution for 3(2y-3)=5y+2(3-y) equation:

3(2y-3)=5y+2(3-y)

We move all terms to the left:

3(2y-3)-(5y+2(3-y))=0

We add all the numbers together, and all the variables

3(2y-3)-(5y+2(-1y+3))=0

We multiply parentheses

6y-(5y+2(-1y+3))-9=0


We calculate terms in parentheses: -(5y+2(-1y+3)), so:

5y+2(-1y+3)

We multiply parentheses

5y-2y+6

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)


We get rid of parentheses

6y-3y-6-9=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5