3(2y-3)=6(y+1)-10

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Solution for 3(2y-3)=6(y+1)-10 equation: 



3(2y-3)=6(y+1)-10

We move all terms to the left:

3(2y-3)-(6(y+1)-10)=0

We multiply parentheses

6y-(6(y+1)-10)-9=0



We calculate terms in parentheses: -(6(y+1)-10), so:

6(y+1)-10

We multiply parentheses

6y+6-10

We add all the numbers together, and all the variables

6y-4

Back to the equation:

-(6y-4)



We get rid of parentheses

6y-6y+4-9=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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