3(2y-4)-2(4y+1)=-20

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Solution for 3(2y-4)-2(4y+1)=-20 equation: 



3(2y-4)-2(4y+1)=-20

We move all terms to the left:

3(2y-4)-2(4y+1)-(-20)=0

We add all the numbers together, and all the variables

3(2y-4)-2(4y+1)+20=0

We multiply parentheses

6y-8y-12-2+20=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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