3(2y-4)-4(3y-1)=-4(2y+1)-(4-y)

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Solution for 3(2y-4)-4(3y-1)=-4(2y+1)-(4-y) equation:



3(2y-4)-4(3y-1)=-4(2y+1)-(4-y)
We move all terms to the left:
3(2y-4)-4(3y-1)-(-4(2y+1)-(4-y))=0
We add all the numbers together, and all the variables
3(2y-4)-4(3y-1)-(-4(2y+1)-(-1y+4))=0
We multiply parentheses
6y-12y-(-4(2y+1)-(-1y+4))-12+4=0
We calculate terms in parentheses: -(-4(2y+1)-(-1y+4)), so:
-4(2y+1)-(-1y+4)
We multiply parentheses
-8y-(-1y+4)-4
We get rid of parentheses
-8y+1y-4-4
We add all the numbers together, and all the variables
-7y-8
Back to the equation:
-(-7y-8)
We add all the numbers together, and all the variables
-6y-(-7y-8)-8=0
We get rid of parentheses
-6y+7y+8-8=0
We add all the numbers together, and all the variables
y=0

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