3(2y-4)-4(3y-1)=-4(2y+1)-(4-y)

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Solution for 3(2y-4)-4(3y-1)=-4(2y+1)-(4-y) equation: 



3(2y-4)-4(3y-1)=-4(2y+1)-(4-y)

We move all terms to the left:

3(2y-4)-4(3y-1)-(-4(2y+1)-(4-y))=0

We add all the numbers together, and all the variables

3(2y-4)-4(3y-1)-(-4(2y+1)-(-1y+4))=0

We multiply parentheses

6y-12y-(-4(2y+1)-(-1y+4))-12+4=0



We calculate terms in parentheses: -(-4(2y+1)-(-1y+4)), so:

-4(2y+1)-(-1y+4)

We multiply parentheses

-8y-(-1y+4)-4

We get rid of parentheses

-8y+1y-4-4

We add all the numbers together, and all the variables

-7y-8

Back to the equation:

-(-7y-8)



We add all the numbers together, and all the variables

-6y-(-7y-8)-8=0

We get rid of parentheses

-6y+7y+8-8=0

We add all the numbers together, and all the variables

y=0

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