3(2y-4)=10+2(3y-1)

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Solution for 3(2y-4)=10+2(3y-1) equation:


Simplifying
3(2y + -4) = 10 + 2(3y + -1)

Reorder the terms:
3(-4 + 2y) = 10 + 2(3y + -1)
(-4 * 3 + 2y * 3) = 10 + 2(3y + -1)
(-12 + 6y) = 10 + 2(3y + -1)

Reorder the terms:
-12 + 6y = 10 + 2(-1 + 3y)
-12 + 6y = 10 + (-1 * 2 + 3y * 2)
-12 + 6y = 10 + (-2 + 6y)

Combine like terms: 10 + -2 = 8
-12 + 6y = 8 + 6y

Add '-6y' to each side of the equation.
-12 + 6y + -6y = 8 + 6y + -6y

Combine like terms: 6y + -6y = 0
-12 + 0 = 8 + 6y + -6y
-12 = 8 + 6y + -6y

Combine like terms: 6y + -6y = 0
-12 = 8 + 0
-12 = 8

Solving
-12 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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