3(2y-4)=15

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Solution for 3(2y-4)=15 equation: 



3(2y-4)=15

We move all terms to the left:

3(2y-4)-(15)=0

We multiply parentheses

6y-12-15=0

We add all the numbers together, and all the variables

6y-27=0

We move all terms containing y to the left, all other terms to the right

6y=27

y=27/6

y=4+1/2

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