3(2y-5)+10=4y+15

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Solution for 3(2y-5)+10=4y+15 equation: 



3(2y-5)+10=4y+15

We move all terms to the left:

3(2y-5)+10-(4y+15)=0

We multiply parentheses

6y-(4y+15)-15+10=0

We get rid of parentheses

6y-4y-15-15+10=0

We add all the numbers together, and all the variables

2y-20=0

We move all terms containing y to the left, all other terms to the right

2y=20

y=20/2

y=10

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