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3(2y-5)=2(y+4)
We move all terms to the left:
3(2y-5)-(2(y+4))=0
We multiply parentheses
6y-(2(y+4))-15=0
We calculate terms in parentheses: -(2(y+4)), so:We get rid of parentheses
2(y+4)
We multiply parentheses
2y+8
Back to the equation:
-(2y+8)
6y-2y-8-15=0
We add all the numbers together, and all the variables
4y-23=0
We move all terms containing y to the left, all other terms to the right
4y=23
y=23/4
y=5+3/4
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