3(2y-7)-4(y+1)=2y-25

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Solution for 3(2y-7)-4(y+1)=2y-25 equation: 


Simplifying
3(2y + -7) + -4(y + 1) = 2y + -25

Reorder the terms:
3(-7 + 2y) + -4(y + 1) = 2y + -25
(-7 * 3 + 2y * 3) + -4(y + 1) = 2y + -25
(-21 + 6y) + -4(y + 1) = 2y + -25

Reorder the terms:
-21 + 6y + -4(1 + y) = 2y + -25
-21 + 6y + (1 * -4 + y * -4) = 2y + -25
-21 + 6y + (-4 + -4y) = 2y + -25

Reorder the terms:
-21 + -4 + 6y + -4y = 2y + -25

Combine like terms: -21 + -4 = -25
-25 + 6y + -4y = 2y + -25

Combine like terms: 6y + -4y = 2y
-25 + 2y = 2y + -25

Reorder the terms:
-25 + 2y = -25 + 2y

Add '25' to each side of the equation.
-25 + 25 + 2y = -25 + 25 + 2y

Combine like terms: -25 + 25 = 0
0 + 2y = -25 + 25 + 2y
2y = -25 + 25 + 2y

Combine like terms: -25 + 25 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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