3(2y-8)+2y=4(y+3)

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Solution for 3(2y-8)+2y=4(y+3) equation: 



3(2y-8)+2y=4(y+3)

We move all terms to the left:

3(2y-8)+2y-(4(y+3))=0

We add all the numbers together, and all the variables

2y+3(2y-8)-(4(y+3))=0

We multiply parentheses

2y+6y-(4(y+3))-24=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

8y-(4y+12)-24=0

We get rid of parentheses

8y-4y-12-24=0

We add all the numbers together, and all the variables

4y-36=0

We move all terms containing y to the left, all other terms to the right

4y=36

y=36/4

y=9

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