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3(2z+1)-5-z=3(1+z)
We move all terms to the left:
3(2z+1)-5-z-(3(1+z))=0
We add all the numbers together, and all the variables
3(2z+1)-z-(3(z+1))-5=0
We add all the numbers together, and all the variables
-1z+3(2z+1)-(3(z+1))-5=0
We multiply parentheses
-1z+6z-(3(z+1))+3-5=0
We calculate terms in parentheses: -(3(z+1)), so:We add all the numbers together, and all the variables
3(z+1)
We multiply parentheses
3z+3
Back to the equation:
-(3z+3)
5z-(3z+3)-2=0
We get rid of parentheses
5z-3z-3-2=0
We add all the numbers together, and all the variables
2z-5=0
We move all terms containing z to the left, all other terms to the right
2z=5
z=5/2
z=2+1/2
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