3(2z+1)-7=26

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Solution for 3(2z+1)-7=26 equation: 



3(2z+1)-7=26

We move all terms to the left:

3(2z+1)-7-(26)=0

We add all the numbers together, and all the variables

3(2z+1)-33=0

We multiply parentheses

6z+3-33=0

We add all the numbers together, and all the variables

6z-30=0

We move all terms containing z to the left, all other terms to the right

6z=30

z=30/6

z=5

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