3(2z+1)=5z+5

Solution for 3(2z+1)=5z+5 equation:

Simplifying
3(2z + 1) = 5z + 5

Reorder the terms:
3(1 + 2z) = 5z + 5
(1 * 3 + 2z * 3) = 5z + 5
(3 + 6z) = 5z + 5

Reorder the terms:
3 + 6z = 5 + 5z

Solving
3 + 6z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
3 + 6z + -5z = 5 + 5z + -5z

Combine like terms: 6z + -5z = 1z
3 + 1z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
3 + 1z = 5 + 0
3 + 1z = 5

Add '-3' to each side of the equation.
3 + -3 + 1z = 5 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 5 + -3
1z = 5 + -3

Combine like terms: 5 + -3 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2