3(2z+1)=6z-2)+14

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Solution for 3(2z+1)=6z-2)+14 equation: 



3(2z+1)=6z-2)+14

We move all terms to the left:

3(2z+1)-(6z-2)+14)=0

We add all the numbers together, and all the variables

3(2z+1)-(6z-2)=0

We multiply parentheses

6z-(6z-2)+3=0

We get rid of parentheses

6z-6z+2+3=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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