3(2z+1.9)+5(2z)+7z=26.4

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Solution for 3(2z+1.9)+5(2z)+7z=26.4 equation: 



3(2z+1.9)+5(2z)+7z=26.4

We move all terms to the left:

3(2z+1.9)+5(2z)+7z-(26.4)=0

We add all the numbers together, and all the variables

59z+3(2z+1.9)-26.4=0

We multiply parentheses

59z+6z+5.7-26.4=0

We add all the numbers together, and all the variables

65z-20.7=0

We move all terms containing z to the left, all other terms to the right

65z=20.7

z=20.7/65

z=3.6315789473684/11.40350877193

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