3(2z+2)-(z-4)=

Solution for 3(2z+2)-(z-4)= equation:

Simplifying
3(2z + 2) + -1(z + -4) = 0

Reorder the terms:
3(2 + 2z) + -1(z + -4) = 0
(2 * 3 + 2z * 3) + -1(z + -4) = 0
(6 + 6z) + -1(z + -4) = 0

Reorder the terms:
6 + 6z + -1(-4 + z) = 0
6 + 6z + (-4 * -1 + z * -1) = 0
6 + 6z + (4 + -1z) = 0

Reorder the terms:
6 + 4 + 6z + -1z = 0

Combine like terms: 6 + 4 = 10
10 + 6z + -1z = 0

Combine like terms: 6z + -1z = 5z
10 + 5z = 0

Solving
10 + 5z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 5z = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 5z = 0 + -10
5z = 0 + -10

Combine like terms: 0 + -10 = -10
5z = -10

Divide each side by '5'.
z = -2

Simplifying
z = -2