3(2z+2)-2(z-4)=

Solution for 3(2z+2)-2(z-4)= equation:

Simplifying
3(2z + 2) + -2(z + -4) = 0

Reorder the terms:
3(2 + 2z) + -2(z + -4) = 0
(2 * 3 + 2z * 3) + -2(z + -4) = 0
(6 + 6z) + -2(z + -4) = 0

Reorder the terms:
6 + 6z + -2(-4 + z) = 0
6 + 6z + (-4 * -2 + z * -2) = 0
6 + 6z + (8 + -2z) = 0

Reorder the terms:
6 + 8 + 6z + -2z = 0

Combine like terms: 6 + 8 = 14
14 + 6z + -2z = 0

Combine like terms: 6z + -2z = 4z
14 + 4z = 0

Solving
14 + 4z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 4z = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 4z = 0 + -14
4z = 0 + -14

Combine like terms: 0 + -14 = -14
4z = -14

Divide each side by '4'.
z = -3.5

Simplifying
z = -3.5