3(2z+2)-4(z-5)=18

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Solution for 3(2z+2)-4(z-5)=18 equation: 



3(2z+2)-4(z-5)=18

We move all terms to the left:

3(2z+2)-4(z-5)-(18)=0

We multiply parentheses

6z-4z+6+20-18=0

We add all the numbers together, and all the variables

2z+8=0

We move all terms containing z to the left, all other terms to the right

2z=-8

z=-8/2

z=-4

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