3(2z+2)-7=29

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Solution for 3(2z+2)-7=29 equation:


Simplifying
3(2z + 2) + -7 = 29

Reorder the terms:
3(2 + 2z) + -7 = 29
(2 * 3 + 2z * 3) + -7 = 29
(6 + 6z) + -7 = 29

Reorder the terms:
6 + -7 + 6z = 29

Combine like terms: 6 + -7 = -1
-1 + 6z = 29

Solving
-1 + 6z = 29

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 6z = 29 + 1

Combine like terms: -1 + 1 = 0
0 + 6z = 29 + 1
6z = 29 + 1

Combine like terms: 29 + 1 = 30
6z = 30

Divide each side by '6'.
z = 5

Simplifying
z = 5

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