3(2z+25)-2(z-12)=78

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Solution for 3(2z+25)-2(z-12)=78 equation: 



3(2z+25)-2(z-12)=78

We move all terms to the left:

3(2z+25)-2(z-12)-(78)=0

We multiply parentheses

6z-2z+75+24-78=0

We add all the numbers together, and all the variables

4z+21=0

We move all terms containing z to the left, all other terms to the right

4z=-21

z=-21/4

z=-5+1/4

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